Ammonia gas can be prepared by the following reaction:
CaO(s) + 2 NH4Cl(s) → 2 NH3(g) + H2O(g) + CaCl2(s)
If 112 g of CaO and 224 g of NH4Cl are mixed the theoretical yield of NH3 is 68.0 g.
If only 16.3 g of NH3 is actually obtained, what is its percent yield?